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Hi Bridget and Mike;
I think the answer lies in the timer / 10 setup for printing out the seconds.
That same timer / 10 needs to be the number that is greater than 3 or 3 is less than.
resett ;first part of the timer
question [2 + 2]
ifelse answer = 4 [text1, ct pr se timer / 10 "seconds] [announce [Wrong answer] stop] ;stop here so you don't get a "too slow" on top of the wrong answer.
ifelse timer / 10 > 3 [announce [too slow]] [ announce [ Good job!] ]
;without the divide by 10, the timer is always going to be greater than 3. Yes?
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